misc: fix creation of inspect_url for link to parent form (#41662)

This commit is contained in:
Frédéric Péters 2020-04-14 11:44:42 +02:00
parent 33e09ae063
commit 10c0486d6d
2 changed files with 5 additions and 1 deletions

View File

@ -6141,6 +6141,10 @@ def test_backoffice_create_carddata_from_formdata(pub, studio):
resp = resp.form.submit(name='button_createcard').follow()
assert 'Card nr. 1-1 created' in resp
# visit inspect page
resp = app.get(formdata.get_url(backoffice=True) + 'inspect')
assert "variables from parent's request" in resp
def test_backoffice_after_submit_location(pub):
create_superuser(pub)

View File

@ -2666,7 +2666,7 @@ class FormBackOfficeStatusPage(FormStatusPage):
r += htmltext(' <div class="value"><span>%(caption)s '
'(<a href="%(inspect_url)s">%(display_name)s)</a></span>') % {
'caption': htmltext('<var>%s</var>') % _('variables from parent\'s request'),
'inspect_url': v['form'].backoffice_url() + 'inspect',
'inspect_url': v['form'].backoffice_url + 'inspect',
'display_name': v['form_display_name'],
}
elif hasattr(v, 'inspect_keys') or isinstance(v, dict):